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Mar 8, 2017 · You are right regarding the meaning of displacement and distance. Displacement denotes how far (in direct line) you are from the origin. Distance is the length covered. As for velocity you need to distinguish between instantaneous velocity and average velocity. Instantaenous velocity. The instantaneous velocity is defined as the time derivative:

Jul 28, 2019 · That is, the tail of this displacement vector is at the earlier position and the head is at the current position. The length of this vector is, generally, the shortest distance between the earlier and current positions. (3) the distance traveled from the earlier position to the current position is not a vector but is, rather, a path length ...

May 18, 2015 · The difference in using Distance vs Displacement is demonstrated in this example: Work = Force x Distance. If I carry an object to and fro 10 metres, the work done would be Force x 20 metres. and. Work = Force x Displacement. If I carry an object to and fro 10 metres, the work done would be Force x 0 metres.

May 15, 2014 · However, keep in mind that in isolation, 'displacement' usually denotes a vector quantity, whereas 'distance' usually the scalar magnitude of the displacement vector. $\endgroup$ – JamalS Commented May 15, 2014 at 10:11

Feb 29, 2016 · With a wave like ##y=A\sin kx## you can see that the displacement (y) varies with distance (x) from some origin, but it does not vary with time. The the displacement-distance graph would be a sine wave, while the displacement-time graph (for each value of x) is a horizontal line.

Feb 26, 2016 · In this graph that I made below, the x-axis is t^2 (time squared), and the y-axis is d (distance). From these axes you can tell that it is a graph showing acceleration . The slope of this line is 36.9 .

Feb 10, 2018 · My teacher is saying that the distance covered will be equal to the area of the trapezium in the graph, but the displacement will be equal to the area of the triangle (with purple hypotenuse). I studied in the internet, and it seemed to me that in this case, the distance will be equal to the displacement (as the velocity was not negative at any ...

Feb 1, 2022 · But we are back to the first paragraph! This would be adding up the motion of the particle over periods where it keeps a constant direction of motion, and this means you are calculating the distance. So it all depends on what you define as "area under the curve". Is it the integral itself (displacement) or the sliced up version (distnace).

Sep 18, 2007 · Why is a parabola formed when a graph of distance(y axis) vs. velocity(x axis) is plotted against each other? (constant acceleration) Homework Equations s=ut+1/2at^2 (guessing?) v^2-u^2 = 2as (guessing?) The Attempt at a Solution I don't know if there is any relationship between veloctiy and distance without knowing the time.

Aug 2, 2013 · The graph is usually displacement-time rater than distance-time. The object starts with a displacement of zero and finishes with a displacement of 5m after 1s - is this correct? To find the units, use the same equation for the units that you used to get the number, but leave out all the bits that don't have units.