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- Factor (x^3+1) (x3 + 1) (x 3 + 1) Remove parentheses. x3 + 1 x 3 + 1 Rewrite 1 1 as 13 1 3. x3 + 13 x 3 + 1 3 Since both terms are perfect cubes, factor using the sum of cubes formula, a3 +b3 = (a+b)(a2 −ab+b2) a 3 + b 3 = (a + b) (a 2 - a b + b 2) where a = x a = x and b = 1 b = 1.www.mathway.com/popular-problems/Algebra/996733
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