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- To solve equations with no solutions, you can follow these steps:
- Look for the same coefficients of the variable on both sides and any different numbers on the two sides. If you find this, there are no solutions1.
- Add or subtract the same value from both sides.
- Clear out any fractions by multiplying every term by the bottom parts.
- Divide every term by the same nonzero value.
- Combine like terms.
- Factor or expand (the opposite of factoring) if needed.
- Recognize patterns, such as the difference of squares.
- Apply a function to both sides if applicable (e.g. square both sides)2.
Learn more:✕This summary was generated using AI based on multiple online sources. To view the original source information, use the "Learn more" links.This trick is based on simplifying and as soon as you see the same coefficients of the variable on both sides and any different numbers on the two sides, you know that there are no solutions. Example: 2 (2x+7)= 5x +12 -x Distribute on left to get 4x +14 Combine like terms on right to get 4x + 12www.khanacademy.org/math/algebra/x2f8bb11595…Here are some things we can do:
- Add or Subtract the same value from both sides
- Clear out any fractions by Multiplying every term by the bottom parts
- Divide every term by the same nonzero value
- Combine Like Terms
www.mathsisfun.com/algebra/equations-solving.html - People also ask
WEBJul 15, 2013 · This trick is based on simplifying and as soon as you see the same coefficients of the variable on both sides and any different numbers on the two sides, you know that there are no solutions. Example: 2 (2x+7)= 5x +12 -x. Distribute on left to get …
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- Solving an equation of quadratic type using the formula x = [-b ± √[(b2 -4ac)]/2a helps us find the roots of the quadratic equation ax2+ bx + c = 0. Plugging in the values of a, b, and c in the formula, we arrive at the solution. Consider the example: 9x2 -12 x + 4 = 0 a= 9, b = -12 and c = 4 x = [-b ± √[(b2 -4ac)]/2a = [12 ± √[((-12)2 -4×9×4)] / (...
WEBDec 28, 2011 · You can solve for the second line by subtracting a multiple of the first equation from the third to solve for the second y value. Substitute that value into the first equation and from there …
- Author: Sal Khan
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