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  2. Solution Since x′ (t) = sint + tcost, y′ (t) = cost − tsint, and z′ (t) = 1, we have x′ (t)2 + y′ (t)2 + z′ (t)2 = (sin2t + 2tsintcost + t2cos2t) + (cos2t − 2tsintcost + t2sin2t) + 1 = t2(sin2t + cos2t) + sin2t + cos2t + 1 = t2 + 2,
    math.libretexts.org/Bookshelves/Calculus/Vector_Calculus_(Corral)/04%3A_Line_and_Surface_Integrals/4.05%3A_Stokes_Theorem
    math.libretexts.org/Bookshelves/Calculus/Vector_Calculus_(Corral)/04%3A_Lin…
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    WEBNov 16, 2022 · StokesTheorem. Let S S be an oriented smooth surface that is bounded by a simple, closed, smooth boundary curve C C with positive orientation. Also let →F F → be a vector field then, ∫ C →F ⋅ …

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  12. Calculus III - Stokes' Theorem - Pauls Online Math Notes

    WEBNov 16, 2022 · Use StokesTheorem to evaluate \(\displaystyle \int\limits_{C}{{\vec F\centerdot d\vec r}}\) where \(\vec F = - yz\,\vec i + \left( {4y + 1} \right)\,\vec j + xy\,\vec k\) and \(C\) is is the circle of radius …

  13. Calculus III - Stokes' Theorem - Pauls Online Math Notes

    WEBNov 16, 2022 · Use StokesTheorem to evaluate \(\displaystyle \iint\limits_{S}{{{\mathop{\rm curl}\nolimits} \vec F\centerdot d\vec S}}\) where \(\vec F = y\,\vec i - x\,\vec j + y{x^3}\,\vec k\) and \(S\) is the …

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