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statistics - What are differences between Geometric, Logarithmic …
Aug 3, 2020 · Now lets do it using the geometric method that is repeated multiplication, in this case we start with x goes from 0 to 5 and our sequence goes like this: 1, 2, 2•2=4, 2•2•2=8, …
why geometric multiplicity is bounded by algebraic multiplicity?
The geometric multiplicity is the number of linearly independent vectors, and each vector is the solution to one algebraic eigenvector equation, so there must be at least as much algebraic …
Calculate expectation of a geometric random variable
2 A clever solution to find the expected value of a geometric r.v. is those employed in this video lecture of the MITx course "Introduction to Probability: Part 1 - The Fundamentals" (by the way, …
Proof of geometric series formula - Mathematics Stack Exchange
Sep 20, 2021 · So for, the above formula, how did they get (n + 1) (n + 1) a for the geometric progression when r = 1 r = 1. I also am confused where the negative a comes from in the …
terminology - Is it more accurate to use the term Geometric …
For example, there is a Geometric Progression but no Exponential Progression article on Wikipedia, so perhaps the term Geometric is a bit more accurate, mathematically speaking? …
How to prove that geometric distributions converge to an …
Dec 21, 2011 · How to prove that geometric distributions converge to an exponential distribution? To solve this, I am trying to define an indexing n n / m m and to send m m to infinity, but I get …
What does the dot product of two vectors represent?
May 23, 2014 · 21 It might help to think of multiplication of real numbers in a more geometric fashion. 2 2 times 3 3 is the length of the interval you get starting with an interval of length 3 3 …
probability - Geometric distribution vs exponential distribution …
Jan 13, 2021 · The geometric and exponential distributions are not the same, since they aren't even defined on the same domain. The geometric distribution lives on a discrete domain, the …
probability - How to get $P (X > x)$ where $X$ is a geometric …
A geometric random variable describes the probability of having n n failures before the first success. There are therefore two ways of looking at this: P(X> x) P (X> x) means that I have x …
Solving for the CDF of the Geometric Probability Distribution
Solving for the CDF of the Geometric Probability Distribution Ask Question Asked 8 years, 4 months ago Modified 8 years, 4 months ago
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