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  2. P (power dissipated) = I2 (current) × R (resistance) or P (power dissipated) = V2 (voltage) / R (resistance) So, using the above circuit diagram as our reference, we can apply these formulas to determine the power dissipated by the resistor. Voltage = 9V Resistance = 100Ω I (current) = 9V / 100Ω or I (current) = 90 mA

    madpcb.com/glossary/power-dissipation/

    There are two possible formulas for power dissipation. The first one requires you to know resistance and current: Alternatively, if you know the current and the voltage drop, you can use the other formula for power dissipation: The two equations are totally equivalent, and at a quick glance, you can see the action of Ohm's law: V=R\cdot I V = R â‹…I.

    www.calctool.org/electrical-energy/power-dissipation
     
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