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  2. x2 does not have an inverse but {x2 | x ≥ 0 } (which says "x squared such that x is greater than or equal to zero" using set-builder notation) does have an inverse.
    www.mathsisfun.com/sets/function-inverse.html
    Solve for y y. Tap for more steps... y = √x y = x y = −√x y = - x Replace y y with f −1(x) f - 1 (x) to show the final answer. f −1(x) = √x,−√x f - 1 (x) = x, - x Verify if f −1(x) = √x,−√x f - 1 (x) = x, - x is the inverse of f (x) = x2 f (x) = x 2.
    www.mathway.com/popular-problems/Algebra/238…
     
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