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Apr 11, 2011 · Agree with @Bogdan. This answer creates a string in which the list elements are joined together with no whitespace or comma in between. You can use ', '.join(list1) to join the …

Jun 14, 2019 · In fact, you can do much more with this syntax. The some_list[-n] syntax gets the nth-to-last element. So some_list[-1] gets the last element, some_list[-2] gets the second to …

Since a list comprehension creates a list, it shouldn't be used if creating a list is not the goal; it shouldn't be used simply to write a one-line for-loop; so refrain from writing [print(x) for x in …

Dec 2, 2013 · writelines() needs a list of strings with line separators appended to them but your code is only giving it a list of integers. To make it work you'd need to use something like this: …

list.count() is a O(N) job (all elements in the list are compared to count) and you are doing this in a loop over N elements, giving you quadratic performance, O(N^2). So for a 10-element list 100 …

To select rows not in list_of_values, negate isin()/in: df[~df['A'].isin(list_of_values)] df.query("A not in @list_of_values") # df.query("A != @list_of_values") 5. Select rows where multiple columns …

Feb 2, 2014 · This makes indexing a list a[i] an operation whose cost is independent of the size of the list or the value of the index. When items are appended or inserted, the array of references …

Oct 15, 2012 · Because it inherits from a list, it basically acts like a list, so you can use functions like index() etc. And because it returns true or false, you can find out if appending succeeded …

However, this still has a problem from quantumSoup's version: It requires your elements to be hashable. That's pretty much built into the nature of sets.** If you're trying to, e.g., subtract a …

Oct 31, 2008 · my_list + another_list creates a third list in memory, so you can return the result of it, but it requires that the second iterable be a list. my_list += another_list modifies the list in …