python check if list contains another

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Checking if any elements in one list are in another [duplicate]
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80edited Feb 3, 2017 at 17:12
You could solve this many ways. One that is pretty simple to understand is to just use a loop.

def comp(list1, list2):
for val in list1:
if val in list2:
return True
return False
A more compact way you can do it is to use map and reduce:

reduce(lambda v1,v2: v1 or v2, map(lambda v: v in list2, list1))
Even better, the reduce can be replaced with any:

any(map(lambda v: v in list2, list1))
You could also use sets:

len(set(list1).intersection(list2)) > 0
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python - Checking if any elements in one list are in …
WEBApr 22, 2013 · list2 = [5, 6, 7, 8, 9] if set(list1) & set(list2): print "Number was found". else: print "Number not in list". The "&" operator gives the intersection point between the two sets. If there is an intersection, a set with the intersecting points will be returned.
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You could solve this many ways. One that is pretty simple to understand is to just use a loop. def comp(list1, list2): for val in list1: if v...
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79
There are different ways. If you just want to check if one list contains any element from the other list, you can do this.. not set(list1).isdisjoi...
18
Your original approach can work with a list comprehension: def listCompare(): list1 = [1, 2, 3, 4, 5] list2 = [5, 6, 7, 8, 9] if [item for item...
9
There is a built in function to compare lists: Following is the syntax for cmp() method − cmp(list1, list2) #!/usr/bin/python list1, list2 = [123...
9
You could change the lists to sets and then compare both sets using the & function. eg: list1 = [1, 2, 3, 4, 5] list2 = [5, 6, 7, 8, 9] if set(lis...
7
I wrote the following code in one of my projects. It basically compares each individual element of the list. Feel free to use it, if it works for y...
1
What if I want to to return the list of occurrence of the values in list1 as compared to list2 as below list1 = [1, 2, 3, 4, 5] list2 = [5, 6, 7,...
0
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WEBApr 6, 2010 · the solution depends on what values you expect from your lists. if there is the possiblity of a repetition of a value, and you need to check that there is enough values in …
Depends on what you mean by "contained". Maybe this: if set(a) <= set(b): print("a is in b").
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48
Assuming that you want to see if all elements of sublist are also elements of superlist: all(x in superlist for x in sublist).
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You might want to use a set. if set(a).issubset(b): print('a is contained in b').
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If you want to validate that all the items from the list1 are on list2 you can do the following list comprehension: all(elem in list1 for elem in...
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Python | Check if a list is contained in another list
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Published: Apr 15, 2019
- Naive Approach. A simple naive approach is to use two for loops and check if the whole list …
  Using list comprehension. A more efficient approach is to use List comprehension. We first …
  Using join and map module. Here we use join to join both lists to strings and then use in …
  Using regular expressions. To check if a list is contained in another list using the Python re …
  Using Recursive method. Steps: If list A is empty, return True, as an empty list is always a …
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How to check if a list contains elements of another list in Python?There are several approaches we can follow for Python List Contains Elements Of Another List in Python. In this example, below Python code below compares two lists, `list1` and `list2`, and checks if all elements in `list2` are present in `list1`. If any element from `list2` is not found in `list1`, the `check` variable is set to `False`.
Python Check if the List Contains Elements of another List
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How to check if a list contains any element from another list?There are different ways. If you just want to check if one list contains any element from the other list, you can do this.. I believe using isdisjoint is better than intersection for Python 2.6 and above. Your original approach can work with a list comprehension: list1 = [1, 2, 3, 4, 5] list2 = [5, 6, 7, 8, 9]
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