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  2. The Goldstone boson equivalence theorem [1-5] in the electro-weak gauge theory is a very popular method for approximating difficult calculations. It states that if A(Wt,ZL,H) is an amplitude for scattering of the longitudinal gauge bosons and the
    lss.fnal.gov/archive/other/osu-279.pdf
    The Goldstone boson equivalence theorem tells us that the amplitude for emission/absorption of a longitudinally polarized gauge boson is equal to the amplitude for emission/absorption of the corresponding Goldstone boson at high energy.
    physics.stackexchange.com/questions/30664/the-…
    The Goldstone-boson equivalence theorem equates the amplitude for longitudinal-vector-boson scattering to the corresponding amplitude for the scattering of the Goldstone bosons of the R gauge.
    experts.illinois.edu/en/publications/goldstone-boso…
     
  3. People also ask
    What is Goldstone boson equivalence theorem?The Goldstone boson equivalence theorem tells us that the amplitude for emission/absorption of a longitudinally polarized gauge boson is equal to the amplitude for emission/absorption of the corresponding Goldstone boson at high energy. I'm wondering what's the physical meaning of this theorem.
    Can Goldstone boson equivalence theorem be used to calculate decay rate?In this thesis, we have studied applications of the Goldstone boson equivalence theorem to decay rate and cross section computations. We have seen examples of how the broken gauge theory structure of electroweak interactions lead to substantial and consistent properties of physical observables.
    How does the Goldstone equivalence theory work?Their Goldstone component E stays constant while the gauge component E = e0 scales as m=k0 m=E and vanishes in the high- energy limit. This produces a suppression factor of the gauge contribution to the amplitude relative to the Goldstone one, which is nothing but the technical statement of the Goldstone Equivalence Theorem.
    What is the equivalence theorem?The theorem states that an amplitude involving longitudinal gauge bosons is equal to one with unphysical Goldstone bosons up to corrections of O(mW /E), i.e. We do not prove the equivalence theorem here, but we follow Ref. and argue why it holds in the special case of the Feynman-’t Hooft gauge.
     
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