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if statement - None value in python dictionary - Stack Overflow
Define your dictionary with. d = {'a': None} rather than. d = {'a': 'None'} In the latter case, 'None' is just a string, not Python's None type. Also, test for None with the identity operator is: for key, value in d.iteritems(): if value is None: print "None found!"Explore further
Python Dictionary: How To Create And Use, With Examples
- Viewed 125k times37edited Sep 23, 2012 at 16:27
Your none values are actually strings in your dictionary.
You can check for 'None' or use actual python None value.
d = {'a':None,'b':'12345','c':None}for k,v in d.items():if d[k] is None:print "good"else:print "Bad"prints "good" 2 times
Or if you Have to use your current dictionary just change your check to look for 'None'
additionally dict is a python built in type so it is a good idea not to name variables dict
Content Under CC-BY-SA license dictionary - Python dict.get() or None scenario - Stack Overflow
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