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    Upvotes5Top Answeranswered Nov 5, 2017 at 8:33

    Collapse your dictionary.

    d = {k : v for d in mylist1 for k, v in d.items()}

    d
    {'age': 23, 'color': 'blue', 'model': 'one'}

    Now, just lookup in constant, O(1) time.

    d['model']
    'one'

    By keeping multiple disjoint dicts in the same list, you're defeating their purpose in the first place.

    If you have multiple possible values with the same keys, use a dict of lists.

    d = {}
    for dct in mylist1:
    for k, v in dct.items():
    d.setdefault(k, []).append(v)

    d
    {'age': [23], 'color': ['blue'], 'model': ['one']}

    Supports multiple values with the same key without overwriting e...

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