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Bokep
- Viewed 30k times5answered Nov 5, 2017 at 8:33
Collapse your dictionary.
d = {k : v for d in mylist1 for k, v in d.items()}d{'age': 23, 'color': 'blue', 'model': 'one'}Now, just lookup in constant, O(1) time.
d['model']'one'By keeping multiple disjoint dicts in the same list, you're defeating their purpose in the first place.
If you have multiple possible values with the same keys, use a dict of lists.
d = {}for dct in mylist1:for k, v in dct.items():d.setdefault(k, []).append(v)d{'age': [23], 'color': ['blue'], 'model': ['one']}Supports multiple values with the same key without overwriting e...
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